As the picture shows, Tang Xiao is flying a kite on the playground.

22.( 1) in Rt△BPQ, PQ = 10m, ∠ B = 30, Then BQ = Cot30× PQ = 1 03 ..................................................................................................................................................... .............................∴AE = sin 30×ab = 12( 103+ 10) ....................................................................................................................................................... .....................................................................................................................................∴AC=2(53+5) =(56+52) (m) .................. ∴ A2–B2 = (2b) 2–B2 = B2 = BC ...................... Xiaoming's conjecture is correct. .......................................................................................................... ....................................................................................................................................................... ..........................................................................................6? 2ACD is an isosceles triangle. ∴∠ BAC = 2 ∠ ACD, while ∠BAC=2∠B, ∴ B = ∠ ACD = ∠ D,? 6? 2∴CBD is an isosceles triangle, that is, CD=CB=a and D = ∠ 6 points. 6? 2∴ACD？ 6? 2∽CBD, 7 points ∴ ADCCDBD =. That is baabc =+c= 10. 10