Traction work w = fs = 3.0×103n× 5.6×103m =1.68×107j.
(2) Fuel mass consumed: m = ρ V = 0.8×103kg/m3×1.5×10-3m3 =1.2kg.
Heat generated by complete combustion of fuel: q = MQ =1.2kg× 4×107j/kg = 4.8×107j.
Heat engine efficiency η = WQ =1.68×107j4.8×107j = 35%.
Answer: (1) The work done by special vehicle traction is1.68×107j;
(2) The heat engine efficiency of this special vehicle is 35%.