In the process of learning analog electricity, I encounter such "subtraction operation", which is really puzzling ~ please ask analog electricity experts for advice ~

According to your circuit diagram, the formula of the relationship between output voltage and input voltage is derived, and it is attached to the bottom of the attached figure. The formula shows that the patented circuit amplifies the DC signal and AC clutter together, and it has no clutter suppression ability at all, which is simply wrong! The output voltage has nothing to do with the R resistor in the original picture and the R2 resistor in the simulation picture.

In order to be prudent, a simulation circuit is specially made on the Multisim platform according to the original drawing. The sum of 2V DC signal and .1V AC signal is used as the total input signal, and the zero adjustment has nothing to do with it, so the input end of the zero adjustment signal led out by that potentiometer is grounded. The ratio of AC interference to DC signal in the input signal is .1/2=5%. No matter how to change this resistance, there is always clutter in the output, and the output clutter is exactly the same as the input, and the ratio of AC interference to DC output is still .1/2=5%!

In fact, the people in the Patent Office generally don't bother to conduct substantive examination. As long as the applicant pays the fee and passes the formal examination, the patent can generally be applied for. Good people should take care of themselves!

puda27 users proposed to add a resistor to the ground at the noninverting input terminal. The resistor can be added, and the AC interference can be eliminated after adding the resistor, but the voltage amplification factor is obviously reduced to below 1!

the key point is that many problems in analog electronic technology are not clearly explained in theory.