Luoj87 (station contact TA) should be sulfonate, which is relatively stable. Because the S-O bond is stable, the corresponding C-O bond is unstable. Your structure is equivalent to an active methylene compound, so hydrogen will be taken away under alkaline conditions, which further reduces the chance of hydroxide ions attacking sulfonate, and racemization will occur. The hydrolysis of carboxylate is that hydroxyl ions attack carbonyl carbon, and sodium hydroxide has enough alkalinity to hydrolyze carboxylate. Lzc463 (contact TA in the station) reaction type is drawn in the figure below, please help us to have a look, thank you! Gauss_ren (in-station contact TA) ethyl ester group is more stable to sodium hydroxide, because sulfonate is easily attacked by HO and leaves lzc463 (in-station contact TA). The above is my experiment, hoping to get the product according to the previous path, but according to my friend's explanation on the second floor, can I think that the second reaction also exists and is easy to happen?
Thank you, friends on the second floor! Lzc463 (station contact TA) Gauss _ Ren, I found a patent that mentioned ethyl ester hydrolysis, and I also tried it. It should be ethyl ester hydrolysis, because if it is sulfonic acid group hydrolysis, sodium p-toluenesulfonate will be obtained, and my solution is ethanol, so I think sodium p-toluenesulfonate is insoluble in ethanol, so I think the statement on the second floor makes sense, but what will happen if it is changed to the above reaction? Lzc463 (station contact TA) Gauss _ Ren, thank you!