(20 14? Known atmospheric pressure drop 1mmHg. Every time the height near the ground increases 12m.

(1) Slowly translate the equipment from A to B at another height. After stabilization, it was found that the water column increased by 40.8mm, the atmospheric pressure decreased by hmmHg, and the water level in the capillary increased by hmm×13.6 = 40.8 mm.

The solution is h=40.8 13.6=3mmHg, then the height difference between AB is △ h = 3x12m = 36m;

(2) The atmospheric pressure is 750mmHg, and the gas pressure in the bottle is: p1= 750 mmHg+20413.6 mmHg = 765 mmHg;

According to the ideal gas state equation, there are p1v1t1= p1v2t2.

Substituting the data, the result is: P2 = 767.55 mmhg；; ;

Therefore, the atmospheric pressure at point B is ppb = P2-pH = 767.55 mmHg-(204+40.8) mmh13.6 = 749.55 mmHg;

So the height difference between A and B is △ H = (750-749.55) ×12 = 5.4m;

So the answer is: (1) higher than 36; (2)5.4