(20 14? Five elements (A, B, C, D, E) are located in the first four periods of the periodic table, and their nuclear charges increase in turn.

The five elements A, B, C, D and E are all located in the first four periods of the periodic table, and their nuclear charges increase in turn, and the sum of nuclear charges is 57; There are two electrons in the L-layer P orbit of atom B, and its extranuclear electron configuration is 1s 222 P 2, so B is a carbon element; The ratio of the number of electrons in the K layer to the number of electrons in the outermost layer of the E atom is 2: 1, and its D orbit is completely filled, so the number of electrons outside the E nucleus =2+8+ 18+ 1=29, so E is a Cu element; The valence electrons of D and B atoms are the same. Combined with the atomic number, it is known that D is Si, and there are three unpaired electrons outside the nucleus of C. If the atomic number is less than Si and its peripheral electronic configuration is 2s22p3, then C is an N element, and the sum of the nuclear charges of the five elements is 57, then the nuclear charges of A are 57-6-7- 14-29 = 1.

(1)C and Si can form * * * valence compounds X and Y with only one central atom, respectively, then X is CH4 and Y is SiH4.

1 pair * * * electrons are formed between C atom and H atom in CH4 molecule, and their electronic types are,; The Si atom in SiH4 has four σ bonds and does not contain lone electron pairs, so the Si atom adopts sp3 hybridization. The common compound formed by N and H is NH3, and its molecular configuration is triangular cone.

So the answer is: sp3 triangle cone;

(2) The highest valence oxides of B and D are CO2 and SiO2, respectively. Because SiO2 _ 2 is an atomic crystal and CO _ 2 is a molecular crystal, it has a high melting point.

So the answer is: SiO 2；; SiO2 _ 2 is an atomic crystal and CO _ 2 is a molecular crystal.

(3) The first ionization energy of element increases with the increase of atomic number in the same period, and the 2p level of element N is in a semi-complete stable state, so the first ionization energy of element N is higher than that of element C; The extranuclear electronic configuration formula of Cu2+ is 1s 222 p 63s 23 p 63d 9,

So the answer is: n; 1s 222 p 63s 23 p 63d 9；

(4) The ion reaction equation of the complex ion formed by Cu2+and the common hydride NH3 of C is Cu2++4NH3═[Cu(NH3)4]2+, so the answer is: Cu2++4NH3 ═ [Cu (NH3) 4] 2+;

(5) As can be seen from the figure, the battery is a face-centered cubic stack. According to the atomic analysis of the vertex, the atom in the center of the face is closest to it, and 1 vertex atom is used for 12 faces, so the coordination number is12;

The radius of aluminum atom is D. As can be seen from Figure C, the diagonal length of a square is 4d, the side length of a cube is 22×4d=22d, the unit cell volume is (22d )3= 162d3, the number of atoms contained in a unit cell is 8× 18+6× 12 = 4 Al, and the relative atomic mass is m// High-quality or satisfactory or special type or recommended answer point time window. iperfer lawyer recommendation service: If your problem has not been solved, please describe your problem in detail and conduct free professional consultation through Baidu Legal Professional Edition. Other similar questions 20 12-04- 18 know that A, B, C, D and E are all elements in the first four periods of the periodic table, and their nuclear charge A < B < C < D < E. 320 12-08-02 has four short-period elements A. 32020-03-2 1 has four short-period elements, A, B, C and D, and their nuclear charges increase in turn. A and C, B and D are homologous elements 420 13-07-22. It is known that ABCDEFG are all short-period main group elements, and their nuclei are increasing in turn. 720 12-04- 16A, b, c, d, e and f are short-period elements of different families, and their nuclear charges increase in turn. The simple substance of (1)D is 620 13-05-27A, b, c, f.22012-1-10a, which is distributed to you for recommendation: f.context. [{ ' URL ':'/d 0 1373 f 082025 AAF 5 1 1aa 256 e 9 edab 64034 f 1a 07？ x-BCE-process = image % 2f resize % 2Cm _ lfit % 2Cw _ 450% 2Ch _ 600% 2c limit _ 1% 2f quality % 2Cq _ 85% 2f format % 2Cf _ auto '， ' contractId':'A24KA00562 '，}，{ ' URL ':/builder/bjh-activity/articlesTask？ taskId = 1598082 & aside = 0 & footer = true & from = 0 '，' src ':'/203 FB 80 e 7 bec 54 e 773 ea 0680 ab 389 b 504 fc 26 a2d？ x-BCE-process = image % 2f resize % 2Cm _ lfit % 2Cw _ 450% 2Ch _ 600% 2c limit _ 1% 2f quality % 2Cq _ 85% 2f format % 2Cf _ auto '，' contractId ':' '，}，{ ' URL ':/s？ word = % E6 % AC % A7 % E6 % B4 % B2 % E6 % 9D % AF & sa = searchpromo _ ozb _ zhidao _ tuijian '，' src ':'/3 BF 33 a 87 e 950352 AAF 5 df 4954 143 fbf2b 2 1 18 b6b？ x-BCE-process = image % 2f resize % 2Cm _ lfit % 2Cw _ 450% 2Ch _ 600% 2c limit _ 1% 2f quality % 2Cq _ 85% 2f format % 2Cf _ auto '，' contractId ':' '，}])； Why is the cost of cancer treatment getting higher and higher? The price of electric cars has dropped many times. Is the quality guaranteed? What impact will the "network toilet" have? Is Huaqiang North's second-hand mobile phone reliable? I recommend f.context ('recbrand', [{"img": "\/86D6277F9E2F07083523F69DFB 24B 899A901F20d? x-BCE-process = image % 2f resize % 2Cm _ lfit % 2Cw _ 450% 2Ch _ 600% 2c limit _ 1% 2f quality % 2Cq _ 85% 2f format % 2Cf _ auto "，" url":"/hm.js？ 6859 ce 5a af 00 FB 00387 e 6434 E4 FCC 925 "； var s = document . getelementsbytagname(" script ")[0]； s.parentNode.insertBefore(hm，s)； })(); window . TT = 1720643950；