(2)F floating = g-f =1.6n-1.4n = 0.2n;
(3) According to F float = ρ water gV, discharge V =F float ρ water G = 0.2n1×103kg/m3×10n/kg = 2×10-5m3;
Because of immersion, V=V row = 2×10-5m3;
So the density of faucet: ρ=0. 16kg2× 10? 5m3=8× 103kg/m3。
Because 8× 103kg/m3 is less than 8.9× 103kg/m3.
So these faucets are not pure copper.
Answer: (1) The mass of each faucet is 0. 16kg. ..
(2) The buoyancy of the faucet when immersed in water is 0.2N 。
(3) The density of this batch of faucets is 8× 103kg/m3. /m3。 The statement of the merchant is wrong.