②t/9=t/6- 1 t= 18
(2) If it is a diamond, it must be a parallelogram.
① when t = 18/5, AO=2, AQ = 0.4.
② When t = 18, point Q is at B, and AB = BO = 2. At this time, the quadrilateral AQOP is a diamond.
(3)① When t = 6 √ 3, AB = BP = 2, AB and BP can make a diamond with an included angle of 30.
② When t = 12-6 √ 3, make a diamond with AB and AP as adjacent sides and an included angle of 30.
③