The ratio of the actual length to the photo length is l car l photo =4.5m0.0 18m=250,
As can be seen from the figure, the distance photo length of the car within t= 1s is s photo =6cm, so the actual distance of the car is s=250×s photo = 250× 6cm = 1500m.
Speed:
v = ST = 15m 1s = 15m/s。
So choose B.