y = x( 12-2x)=-2x 2+ 12x,
(2) Let the length of the side perpendicular to the wall be xm,
Then x( 12-2x)= 16,
The solution is x 1 =2, x 2 = 4,
When x=2, 12-2x=8,
When x=4, 12-2x=4,
So the length of the side perpendicular to the wall is 2 meters or 4 meters;
(3) Let the length of the side perpendicular to the wall be ym,
Then y( 12-2y)=20,
Finishing, -2y 2+12y-20=0,
△= 144-4×(-2)×(-20)=- 16