Let me give you a general example:
Let z = axy+ times 2, where A and B are constants and X and Y are variables.
Let's find a = 1, b = 2 and x = 3. To find the integral of y to [0, 1], the steps are as follows:
First, execute the following command: YY = int ('a * x * y+b * y 2',' y', 0, 1).
The following results will be displayed:
yy =
1/2*a*x+ 1/3*b
Then enter the following command:
a = 1； b = 2； x = 3；
yyyyy=subs(yy)
The results are as follows:
yyyyy =
2. 1667
I don't know. Is that clear? ! ! ! ! ! !