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( 1)tan∠CDB=33,

∴∠CDB = 30°, that is, the slope angle of the new slope surface is 30;

(2)∫CBBD = 33,BC= 12

∴DB=3BC= 123,

In Rt△ABC, tan∠CAB=CBBA= 1

∴ab=bc= 12, 12-( 123- 12)=24- 123≈3.24