The angle between AC and BC and Y axis is 30, and the tension of ropes AC and BC is equal.
C in the vertical direction of the equilibrium state, 2F pulls cos30 =mg.
de:F = mg 2 cos 30 = 102×32 = 1033n?
(2) Analyze the stress in Figure 2 C, establish a rectangular coordinate system, and know from the geometric relationship that ∠ BAC = 37.
Establish an equilibrium equation, the vertical direction: F-pull +F-pull sin37 =mg?
Get: f tension = 6.25 n.
Horizontal direction: f pull cos37 =F F f.
Get: F=5N.
Answer: (1) Now let the door curtain hang in the air, as shown in figure 1, and the tension in the rope is1033 n;
(2) If the customer pushes the door curtain with horizontal thrust F, it is simplified as C just hangs below the B end at this time, BC = 3 cm, as shown in Figure 2. In this state, the Zhang Liwei in the rope is 6.25N and the horizontal thrust F is 5 N. 。