(1) Volume of liquid overflowing from the overflow cup:
V overflow =V line = 50cm3 = 50x 10-6m3,
(2) The buoyancy a receives is:
f float = GA-f 1 = 3.2N-2.6N = 0.6N,
According to Archimedes principle, F float = ρ liquid? g? Line v:
ρ liquid =F floating gV row = 0.6n10n/kg× 50x10? 6 m3 = 1.2× 103kg/m3;
(3)∫G = mg,
∴ma=gag=3.2n 10n/kg=0.32kg,
The density of the metal block a is:
ρA=mAVA=0.32kg50× 10? 6 m3 = 6.4× 103kg/m3;
So the answer is: (1) 50; (2) 1.2× 103; (3)6.4× 103.