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(1) Substitute Y = 4 into Y =-X+ to get X = 1.
The coordinate of point ∴ C is (1, 4).
When y = 0 and -x+= 0,
∴ X = 4。 The coordinate of point B is (4,0).
(2) If CM ⊥ AB is in m, then cm = 4 and BM = 3.
∴ BC = = 5.
∴sin∠ ABC = =。
① when 0 < t < 4, let QN ⊥ OB be n,
Then qn = bqsin ∠ ABC = t.
∴ S = OP QN = (4- t )× t =- t 2 + t (0< t