So the answer is: 2KHSO4? Turn it on? . ? k2s2o 8+H2↑；
(2) The anode is an anion discharge, which generates a gas that can oxidize I-, if it is colored, it should be O3, which can be understood as O2 generated by OH- discharge, and O2 is further converted into O3 under the discharge condition;
So the answer is: O3;
(3) According to the information, ice cubes should be added to the beaker every half an hour. The reason is that potassium persulfate is easy to decompose, which reduces the water temperature and ensures that the temperature during electrolysis is below 5℃, so it needs to be generated at low temperature;
So the answer is: reduce the water temperature to ensure that the temperature during electrolysis is below 5℃;
(4) Ethanol and diethyl ether are mutually soluble organic substances, which can be separated by distillation because of their different boiling points;
So the answer is: distillation;
(5)I- is easily oxidized, such as O2 in the air, which needs to be sealed during the experiment, and starch and I2 are blue. In this experiment, when I2 is consumed, the blue color will fade, indicating the end of the reaction. Find the relationship from the equation:
K2S2O8~I3-~I2~2S2O32-
270 2
m(K2S2O8) cV 10-3
w(k2s 2 o 8)= m(k2s 2 o 8)0.25 = 270×cv× 10？ 32×0.25× 100% = 54cV %；
So the answer is: 54cv %；;
(6) 6) The valence of Mn increased from +2 to +7, and that of S decreased from +7 to +6. According to the conservation of gain and loss electrons, it is determined that there is H+ in the product. Finally, it is determined that there is H2O in the reactant by the conservation of H atom, and the ionic equation is 2mn2++5S2O82-+8H2O ═ 2mno4-+60.
So the answer is: 2mn2++5S2O82-+8H2O ═ 2mno4-+10so42-+16h+