An athlete's performance: 19? 18? 18? 26? 2 1? 20? 35? 33? 32? 30? 47? 4 1? 40
Player b's score: 17? 17? 19? 19? 22? 25? 26? 27? 29? 29? 30? 32? 33
For, the range is the difference between the maximum and minimum values in the data.
It can be concluded from the data in the figure that the fractional extreme difference of A is 47- 16=2 1, and that of B is 33- 17= 16.
The extreme difference in the scores of athletes who get A is greater than that of athletes who get B, so A is correct.
For B, the data of A are arranged from small to large: 18? 18? 19? 20? 2 1? 26? 30? 32? 33? 35? 40? 4 1? 47
The median number is 30, so the median score of player A is 30 and the median score of data B is 26.
Therefore, the median score of player A is greater than that of player B, so B is correct;
For C, it is not difficult to get that the average score of player A is about 29.23 and that of player B is 25.0.
Therefore, the average score of player A is greater than that of player B, so C is correct;
For D, calculate the variance of the results of two athletes, A and B, and the results with small variance are more stable.
The variance of can be calculated as follows:
S2 A =？ 1 13[( 19? 29.2)? 2+( 18+29.5)? 2+…+(40? 29.2)? 2]=88.22,
Similarly, the variance of b is: S B 2=29.54.
Because the variance of B is smaller than that of A, B is more stable than A, so D is incorrect.
So choose d