Because we don't know the center of the circle.
So we can set its center as C(x, y)
Then (x-2) 2+(y-2) 2 = (x+3) 2+(y-1) 2 = R2.
Because the slope of the straight line is 2x+3y- 10=0 k=(-A/B)=-2/3.
CP is perpendicular to the straight line.
So the slope of the straight line where CP is located is Kcp=- 1/(-2/3)=3/2.
That is, (Y-Y 1)/(X-X 1)=3/2.
Replace the others with the coordinates of point p.
(Y-2)/(X-2)=3/2
Use x for y or y for X.
Y=3/2X- 1。
Substitution can find X=0, Y= 1.
So the coordinate of the center of the circle is (0, 1).
r^2= 13
So the standard equation of a circle is x 2+(y+1) 2 =13.
Hoo ~' OK.
It is more difficult to find the coordinates of the center of the circle.
You must do it yourself.
We also have an exam tomorrow.
It's tiring to take the exam for three days.
In high school, I didn't study math very hard.
Alas, I wonder if I will fall back to several places this time.