If a, b, m and h are isosceles trapezoid, then BM=AH and AB are parallel to MH, then the line where MH is located can be considered as
Y = 4/3x+x0。 When x=0, y=x0. That is, OM=x0.
Because OM=OA, we can get OA=6 and OB=8 from the function Y = 4/3x+8. That is to say, the straight line where MH is located is Y = 4/3x+6. And BM=OB-OM=OB-OA=2, then AH=2.
Suppose point H is (x 1, 4/3x 1+6), then AH=(2-x 1)? +(4/3x 1+6)？
Solve the equation (2-x 1)? +(4/3x 1+6)？ =2, you can get x 1, and then the coordinates of point h come out.