For spacecraft M, gravity provides centripetal force: GMM (R+H) 2 = M (2π t) 2 (R+H).
For the object m 1 on the surface, gravity is equal to universal gravitation: GMM1R2 = m1g.
From the above two equations, it is found that the height of the spacecraft from the ground h = 3R2GT24π 2? rare
(2) According to v = 2π rt? get
Running speed v = 2π (r+h) t = 32π r2gt.
A: (1) The height h of Shenzhou-10 spacecraft from the ground is 3R2gT24π2? r；
(2) The speed V of Shenzhou-10 spacecraft orbiting the earth is 32πR2gT. ..